Theorethical (math) questions about spur gears

Re: Theorethical (math) questions about spur gears

NoobMan — Sun, 20 Nov 2011 06:52:25 -0500

More or less on the topic, can anybody tell me what is the exact distance between centers of gears for wade extruder pls?

And generally speaking, a shortcut on how to identify the distance between centers backwards from the gear aspect/looks.

Cheers.

questions about gear wheel

lieuthnant — Sun, 20 Nov 2011 06:36:38 -0500

I would like to write a function with Matlab. The function must draw me a gearwheel of 50 teeth . But I would like to use the instruction " Plot polar" . I have already written the code but he doesn't draw ho i want. Here is also my code. Perhaps find someone what is my mistake.
greetings

code:
-----------------------------------------------------
function[]=neu_rad()

Ri=49.92; %internal radius
Ra=52; % Expresses radius
for alfa=0:0.1:7.2 % draw one period
b=mod(alfa,7.2);
if (b<4.3)
X=Ri*sin(alfa);
Y=Ri*cos(alfa);
else if(b>=4.3 && b<=4.7)
z=0.48712*b+4.27; %straight equation positive upward gradient
X=Ri*sin(alfa)+z*sin(alfa);
Y=Ri*cos(alfa)+z*cos(alfa);

else if (b>4.7 && b<=7)
X=Ra;
Y=Ra;

else if (b>=7 && b<=7.2)
z=-0.48712*b+10.71; %straight equation negative upward gradient
X=Ri*sin(alfa)+z*sin(alfa);
Y=Ri*cos(alfa)+z*cos(alfa);
end
end
end

end
plot(X,Y,'b-')
axis equal
hold on
end

Re: Theorethical (math) questions about spur gears

Traumflug — Thu, 19 Aug 2010 17:41:01 -0400

The minimum number of teeth is independent from the module. It's 14 to 17 for gears with contact diameter = pitch diameter .

Re: Theorethical (math) questions about spur gears

SUJOY BASAK — Thu, 19 Aug 2010 13:59:05 -0400

Please tell me what is the minimum number of teeth required to design a spur gear of module 12.

Re: Theorethical (math) questions about spur gears

Greg Frost — Tue, 20 Jul 2010 07:41:25 -0400

You may also want to look at my openscad script: [www.thingiverse.com]

Re: Theorethical (math) questions about spur gears

MattMoses — Tue, 20 Jul 2010 00:11:48 -0400

Thanks! I added a link to your file from the wiki article. -Matt

Re: Theorethical (math) questions about spur gears

fdavies — Sun, 18 Jul 2010 19:18:29 -0400

I have slightly modified your main script file so that it will run with Octave. I have attached the resulting file.

F Davies

Re: Theorethical (math) questions about spur gears

MattMoses — Sun, 18 Jul 2010 14:49:52 -0400

I posted some MATLAB scripts for drawing gears that might be useful here [www.reprap.org]

The involute drawing function is pretty clunky and basic, but it might be something you could modify to suit your needs.

-Matt

Re: Theorethical (math) questions about spur gears

murrayd — Wed, 14 Jul 2010 10:18:37 -0400

Depending on the ratios, which affects how many teeth are being expected to contact at once, you can separate the pitch circles and adjust the addendum and dedendum (flank profile outside and inside of the pitch circle) to strengthen the teeth, turn down the outer diameter to produce stub teeth, or both.

Re: Theorethical (math) questions about spur gears

khiraly — Tue, 13 Jul 2010 06:52:59 -0400

> You 14/144 pair nicely shows where an undercut would be necessary. That's yet another story ;-)

I dont think it is undercut problem. Wrong involute profile curve. The second screenshot
proves it to me at least;-)

Re: Theorethical (math) questions about spur gears

Traumflug — Tue, 13 Jul 2010 06:49:50 -0400

Quote

Also when the Root diameter is bigger then the base diameter, I made the two diameter equal.

Why? The only measure for the root diameter is to make room for the opposite's wheel teeth. Everything smaller stresses the material unneccessarily.

You 14/144 pair nicely shows where an undercut would be necessary. That's yet another story ;-)

Re: Theorethical (math) questions about spur gears

khiraly — Tue, 13 Jul 2010 06:46:48 -0400

Looks like it is not the right solution. Here is a screenshot demonstrating it:

4789909862_2d294ac22e_b.jpg

magenta: 14 teeth gear (m=2)
white: 144 teeth gear without DB=DR modification (m=2)
yellow: 144 teeth gear with DB=DR modification (m=2)

So it is clear, that the correct method would be finding the intersection
mathematically, and trim each involute profile curve by DR.

I gave up here. I think i just wait a couple of week to give an another shoot
to this problem. Until then I use gears with small number of teeths (the program
warns when the DR>DB ). With m=2 I can get 41 teeth, so it should be enough.

DR: Root diameter (the bottom of the tooth)
DB: base diameter (starts the involute profile from here)

Best regards,
Laszlo
[blog.arcol.hu]

Re: Theorethical (math) questions about spur gears

Traumflug — Tue, 13 Jul 2010 06:43:03 -0400

Quote

(I use a=m, while he is using somewhat smaller).

He's right, but doesn't use the most standardized design. You need some clearance between your root circle and the tooth top of the opposite wheel, so always a < b. Standards recommend a = m and b = 1.2 * m.

BTW., this online gear generator uses a contact diameter different from the pitch diameter (check the boxes to the right of the input field). This is possible and allows lower teeth numbers, but isn't the most simple design.

Re: Theorethical (math) questions about spur gears

khiraly — Tue, 13 Jul 2010 06:33:38 -0400

I semi-fixed the tooth issue. Now the tooth and gap has the same width at the pitch diameter.
Also when the Root diameter is bigger then the base diameter, I made the two diameter equal.

Is is almost good. Here is a screenshot:

4789264713_f86e1d8e09_b.jpg

However the bigger gear is 144 teeth version, and the involute profile seems a bit too straight to me.

Laszlo
[blog.arcol.hu]

Re: Theorethical (math) questions about spur gears

khiraly — Tue, 13 Jul 2010 04:02:23 -0400

Traumflug Wrote:
-------------------------------------------------------
>> > Base circle diameter = number of teeth * module
>> * cos(20deg)
>>
>> This is not correct either. It is the root circle
>> diameter.
>
> Base circle is the circle your convolution is
> perpendicular on, right? No mistake on this one on
> my side.

Yepp, you are right. From the base circle starts the involute line.
This was my mistake.

> It's quite possible for the base diameter being smaller than the root diameter.

This is the key factor of my troubles.
So if I understand right, the goal is to have the height of a teeth: 2b+2a
The outside diameter is fix (pitch diameter+2a)
The bottom of the teeth is always the root circle, even if it is bigger then the
base circle.

Thank you. I'll fix my script later today and examine it further. The issue.

Also I found this online gear generator:
[woodgears.ca]

Where the tooth spacing(mm) is equal to module * pi.
If I write for example m=2, N=14 (tooth spacing is 6.14)
Then I get almost exactly the same result then my drawing (I can check it
there is a shaft hole diam(mm) input field), the pitch diameter matches, the
base diameter matches. Only the outside and root diameter does not match,
because he uses different relations between module and addendum.
(I use a=m, while he is using somewhat smaller).

So finally everything clears up.

Best regards,
Laszlo
[blog.arcol.hu]

Re: Theorethical (math) questions about spur gears

Traumflug — Tue, 13 Jul 2010 02:55:57 -0400

Quote

Pitch circle diameter = number of teeth * module / pi

Pitch circle diameter = number of teeth * module

Sorry for confusing circular pitch and module myself.

Quote

> Base circle diameter = number of teeth * module * cos(20deg)

This is not correct either. It is the root circle diameter.

Base circle is the circle your convolution is perpendicular on, right? No mistake on this one on my side.

Quote
original posting
In that case base diameter [DB] is smaller then root diameter [DR] !

It's quite possible for the base diameter being smaller than the root diameter.

There's also a minimum number of teeth for workable wheel combinations constructed from convolutions alone, which is 14 - 17 teeth on the smaller wheel. To get a lower tooth number you need extra considerations, for example a contact diameter differing from the pitch diameter, a smaller tooth height (standardized at a = module, b = 1.2 * module) or a different contact angle (standardized at alpha = 20deg). Neither of these are mentioned in the initial set of formulas.

Re: Theorethical (math) questions about spur gears

khiraly — Tue, 13 Jul 2010 02:14:57 -0400

Also seems like the formulas Im using matches with this example:
[www.sdp-si.com]

python arcolgears.py -n 24 -m 3.0
N: 24 m: 3.0 a: 3.0 b: 3.75 PA: 20.00 deg
DR: 64.5 DB: 67.6578686966 D: 72.0 DO: 78.0

Or this pdf:
[mdmetric.com]

Or this:
[www.qtcgears.com]

Where even explain the pitch diameter and circular pitch:
pitch diameter = N * m
circular pitch = m * pi

The problem is, there are number of teeths, where these formulas are simply does not work.
It will always happen (above a teeth number) that the
base diameter (pitch diameter * cos pressure angle) will be smaller then the root diameter (pitch diameter - 2*dedendum).

Im a bit lost, because Im followed metric calculations, while every book seems to be
US based.

Re: Theorethical (math) questions about spur gears

khiraly — Mon, 12 Jul 2010 18:53:43 -0400

> You want tooth thickness and tooth gap to be the same at the pitch circle, not at the base circle.

Correct, you are right. My mistake.

> Pitch circle diameter = number of teeth * module / pi

It is wrong. If you look at the 9 teeth gear, the outside diameter is 22mm, the root diameter is 13mm.
If we solve your equaton: P = 9*2/pi = 18/3.14 = 5.7 mm
The pitch diameter cant be smaller then the root diameter!

> Base circle diameter = number of teeth * module * cos(20deg)

This is not correct either. It is the root circle diameter. The base circle diameter is P-2*b
Which is bigger then the root circle diameter. (until I dont play with the teeth numbers).

Anyway, thank you catching the tooth-gap distance issue!
I will look into it, and correct the math in my program.

Best regards,
Laszlo

Re: Theorethical (math) questions about spur gears

Traumflug — Mon, 12 Jul 2010 18:05:32 -0400

You want tooth thickness and tooth gap to be the same at the pitch circle, not at the base circle.

Module = circular pitch / pi --> choose one of these two to be constant on all participating gears

Pitch circle diameter = number of teeth * module / pi
Base circle diameter = number of teeth * module * cos(20deg)
Axes distance = 0.5 * module * ( teeth number wheel one +- teeth number wheel two ) // plus/minus for outside/inside gears

When constructing gears, outside diameter and root diameter are secondary citizens. Get the other two right, first. Then draw the convolutions. Chopping teeth at the top and at the bottom is the last step.

Construction gear teeth is a pretty complicated matter, the above doesn't mention e.g. special cases for low tooth number wheels or leveled material stress.

Theorethical (math) questions about spur gears

khiraly — Mon, 12 Jul 2010 15:41:43 -0400

Hi,

Im studying spur gears since two days already. I have some math questions about gears.
Im seeing many spur gears with 67, 127 teeths, and Im unable to generate it.

There are basically two standard for gears: metric and US. The metric is basically
defined with module [m], number of teeth [N] and pressure angle [PA].

The US version is defined using diametral pitch[P] instead of module.

For nomenclature here is a nice wikipedia picture:

714px-Gear_words.png

There are some important circles (diameters) along the gear.
These are:
Root diameter [DR] = P*cos(PA)
Base diameter [DB] = P-2*b
Pitch diameter [P] = N*m
Outside diameter [DO] = P+2*a
addendum [a] = m
dedendum [d] = 1.25*m (it varies between standards, and module(m) sizes)

Lets take the following example:
N: 42 m: 2.0 a: 2.0 b: 2.5 PA: 20.00 deg
DR: 79.0 DB: 78.934180146 D: 84.0 DO: 88.0

In that case base diameter [DB] is smaller then root diameter [DR] !
So it cant be generated.

So I have no idea how am I supposed to generate a gear with high enough teeths.
It would be really awesome to find a dxf drawing of a metric gear with 127 teeth!
It exists, many catalogue does list them.

Here are some pictures to show the problem.

Gear with 9 teeth (works):
N: 9 m: 2.0 a: 2.0 b: 2.5 PA: 20.00 deg
DR: 13.0 DB: 16.9144671741 D: 18.0 DO: 22.0

4787107749_d8aaedb6b1_b.jpg

Gear with 17 teeth (works):
N: 17 m: 2.0 a: 2.0 b: 2.5 PA: 20.00 deg
DR: 29.0 DB: 31.9495491067 D: 34.0 DO: 38.0

4787107765_4a8d20cb80_b.jpg

Gear with 41 teeth (works, but barely):
N: 41 m: 2.0 a: 2.0 b: 2.5 PA: 20.00 deg
DR: 77.0 DB: 77.0547949044 D: 82.0 DO: 86.0

4787107769_463af1634a_b.jpg

Gear with 67 teeth (does not work. from 42 teeth, it does not work):
N: 67 m: 2.0 a: 2.0 b: 2.5 PA: 20.00 deg
DR: 129.0 DB: 125.918811185 D: 134.0 DO: 138.0

4787107773_7dc4b39ea0_b.jpg

G67 closeup, to better see the problem:

4787107779_f2c6b2f382_b.jpg

I basically followed this site:
[www.cartertools.com]
And cross-checked with this: [www.roymech.co.uk]

For math please look at this site:
[mathworld.wolfram.com]

List of definitions, and formulas:
[www.gizmology.net]

Here is a gear generator flash site: [woodgears.ca]
gears related standards: [www.gearandracks.com]

Maybe someone is more deeply digged than I, and can shed some light, what is the correct
math to generate high number teeths (67, 127, 200 teeths).

Forrest, if you are reading this, maybe you figured it out already, because you are working
other type of gears too (herringbone gears).

Any idea, links, etc are welcome!

Best regards,
Laszlo
[blog.arcol.hu]