Enclosure math- why they're so important and how to make one. December 22, 2014 09:14PM |
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Re: Enclosure math- why they're so important and how to make one. April 07, 2015 08:57AM |
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Quote
sungod3k
I like the idea and even calming down the airflow would be positive, however my main concern would be hotend cooling. Which would require a either a big hose getting outside air onto the hotend and model cooling fans or a pressurized fan that sits outside and blows in air though a smaller tube.
I have been thinking about pressurized fan already independent of the enclosure. It would make aiming the model cooling airflow much easier if you had 2-4 little tubes blowing on you model instead of mounting a fan (or two) and funnels that cover only half of the model anyway,
Re: Enclosure math- why they're so important and how to make one. April 07, 2015 09:41AM |
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Re: Enclosure math- why they're so important and how to make one. April 07, 2015 02:11PM |
Registered: 10 years ago Posts: 869 |
I know it's an older post, but your numbers are incorrect for what you're trying to compute as you are confusing thermal conductivity with heat transfer coefficient.Quote
SamS
Let's assume the total surface area of an enclosure is about a square meter. That's a five-faced cube with ~450mm sides, and we're going to assume the table or whatever it's on isn't giving us any heat loss. I should probably account for a few more things, and my system is a little too ideal but this is just to illustrate a concept.
So now let's use 6mm polycarbonate. It seems to be a pretty simple, clear solution to a bed. at 1 m^2 and .19 W/mK for polycarbonate, and a temp difference of 60C (Room temp of about 20, goal is about 80) That's 1900 watts. This exact number doesn't mean a whole lot because of the crude assumptions, but consider that a 12V heated bed pushing 10 amps is only giving your system 120 watts. Not even one-tenth.
Re: Enclosure math- why they're so important and how to make one. April 07, 2015 03:38PM |
Registered: 9 years ago Posts: 30 |
Quote
cdru
I know it's an older post, but your numbers are incorrect for what you're trying to compute as you are confusing thermal conductivity with heat transfer coefficient.Quote
SamS
Let's assume the total surface area of an enclosure is about a square meter. That's a five-faced cube with ~450mm sides, and we're going to assume the table or whatever it's on isn't giving us any heat loss. I should probably account for a few more things, and my system is a little too ideal but this is just to illustrate a concept.
So now let's use 6mm polycarbonate. It seems to be a pretty simple, clear solution to a bed. at 1 m^2 and .19 W/mK for polycarbonate, and a temp difference of 60C (Room temp of about 20, goal is about 80) That's 1900 watts. This exact number doesn't mean a whole lot because of the crude assumptions, but consider that a 12V heated bed pushing 10 amps is only giving your system 120 watts. Not even one-tenth.
Thermal conductivity is how well heat flows within a material. For our heater blocks, we want heat to flow very well so that it's even and no hot spots right next to the heater but not on the far side of the melt chamber. For this, we choose aluminum or brass because they have a "k value" in the hundreds of W/(m K). But because the thermal conductivity is so good, this is why all metal hot ends heat breaks aren't made of aluminum...it would wick all that heat away up into the cooling fins defeating the purpose of a heat break. So instead they are made of stainless steel which has a k value of around 16 W/(m K). Polycarbonate has a k value of .19 W/(m K). It would make a excellent material for a heat break as it resists the transfer of heat...if only it could withstand the heat (it can't). In terms of your enclosure, 1900 watts is the rate of heat transfer WITHIN THE POLYCARBONATE if you had the inside surface at 80 degrees and the outside at 20. Slowly over time though the outside surface would raise in temperature as more heat from the inside was generated. That is then where the heat transfer coefficient comes into play...
The heat transfer coefficient is basically how well the material gives off heat, usually in the form of convection between solids and a fluid or gas. This multiwall polycarbonate sheet like was shown above has a coefficient of 3.7W/m²K. I found a few solid 6mm sheets that had a coefficient of 3.5W/m²K. A box with a surface area of 1 meter made of solid polycarbonate 6mm thick would lose 3.5 W/m²K * 1m * 60 degrees = 210 watts, NOT 1900 watts.
Re: Enclosure math- why they're so important and how to make one. April 07, 2015 05:27PM |
Registered: 10 years ago Posts: 869 |
Feel free to point them out. Or if I need to provide sources to back up my math I can do that as well. All my units should be metric (Watts, meters, Kelvin) and the temperature component is actually a delta temperature change so degrees Celsius or Kelvin doesn't matter...they are the same just offset 273.15 from each other. I originally had just degrees and implied Celsius so I did update my post so that I removed any ambiguity about what "degrees" I was talking about. I also double checked my units to make sure they used the proper abbreviations.Quote
Djkingsley
I think that there is a Celsius, Fahrenheit, and Kelvin conversion issue in your equation.
Re: Enclosure math- why they're so important and how to make one. April 07, 2015 06:26PM |
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Re: Enclosure math- why they're so important and how to make one. April 07, 2015 09:39PM |
Registered: 9 years ago Posts: 104 |
Quote
SamS
Is getting insulation foam easy in Europe? How about Australia/NZ? I know there are some strange restrictions on it in California so I guess I just assumed it was scarce.